Question

In a circket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that he did not hit a boundary.

Answer 1

Number of balls played by the batsman = 30

Number of balls in which he hits boundaries = 6

∴ Number of balls in which he did not hit a boundary = 30 − 6 = 24

P(Batsman did not hit a boundary) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{balls}\mathrm{in}\mathrm{which}\mathrm{he}\mathrm{did}\mathrm{not}\mathrm{hit}\mathrm{a}\mathrm{boundary}}{\mathrm{Number}\mathrm{of}\mathrm{balls}\mathrm{played}\mathrm{by}\mathrm{the}\mathrm{batsman}}=\frac{24}{30}=\frac{4}{5}$

Thus, the probability that he did not hit a boundary is $\frac{4}{5}$.