Question

In a cricket match , a boundary 6 times out of 30 balls he plays.Find the probalility that on a ball played:

(i) he hits boundary (ii) he does not hit a boundary.

Answer 1

Total balls played (n) = 30

No of boundarries=6

(i) When the batsman hits the boyndary =6

$\therefore$ m=6

$\therefore P\left(A\right)\frac{m}{n}=\frac{6}{30}=\frac{1}{5}=0.2$

(ii) When the batsman does not hit the boundary (m) =30-6=24

$\therefore$ Probability P(A)=$\frac{m}{n}=\frac{24}{30}=\frac{4}{5}=0.8$