Question

In a cricket match, Jason hits a boundary in $6$ out of $42$ balls he plays. Find the probability that he will not hit a boundary on the next ball.

• A. $\frac{6}{7}$
  
• B. $\frac{1}{7}$
  
• C. $\frac{2}{7}$
  
• D. $\frac{1}{6}$
  

Answer 1

The correct option is A $\frac{6}{7}$


Jason hits a boundary $6$ out of $42$ balls.
Number of times Jason did not hit the boundary $=42-6=36$

$36$ out of $42$ times Jason did not hit a boundary.

Number of favorable outcomes $=36$
Total number of outcomes $=42$

The probability $\text{P(E)}$ that Jason did not hit the boundary is:

$\text{P(E)}=\frac{36}{42}=\frac{6\times 6}{6\times 7}$

$\text{P(E)}=\frac{6}{7}$


The probability that Jason did not hit the boundary is $\frac{6}{7}$.

Therefore, option (a.) is the correct answer.