In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is:

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Solution

The correct option is B
7

Lower limit of the class is $= 10 - (\frac{6}{2})$
$= 10 - 3 = 7$

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In a frequency distribution, the mid-value of a class is $10$ and the width of the class is $6$ . The lower limit of the class is:
A) $6$
B) $7$
C) $8$
D) $12$

(i) Find the class mark of the class 90-120.
(ii) In a frequency distribution, the mid-value of the class is 10 and width of the class is 6. Find the lower limit of the class.
(iii) The width of each of five continuous classes in a frequency distribution is 5 and lower class limit of the lowest class is 10. What is the upper class limit of the highest class?
(iv) The class marks of a frequency distribution are 15, 20, 25, .... Find the class corresponding to the class mark 20.
(v) In the class intervals 10-20, 20-30, find the class in which 20 is included.

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In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is:

The correct option is B 7 Lower limit of the class is =10−(62) =10−3=7

The correct option is B
7

Lower limit of the class is $= 10 - (\frac{6}{2})$
$= 10 - 3 = 7$