Question

In a hot water heating system, there is a cylindrical pipe of length $28m$ and diameter $5cm$. Find the total radiating surface in the system.

Answer 1

Given:

$H=28$m, $R=\frac{5}{2}=2.5$cm $=0.025$m $\left(\frac{2.5}{100}\right)$

$\Rightarrow$CSA of pipe (cylindrical)$=2\pi rh$

$=2\times \frac{22}{7}\times 0.025\times 28$m${}^2$

$=4.4$m${}^2$