In a metre bridge, the gaps are closed by two resistances P & Q & the balance point is obtained at 40 cm. when Q is shunted by a resistance of 10Ω, the balance point shifts to 50 cm. the values of P & Q are
respectively
R=Sl(100−l) ⇒P=Q×4060=23Q
when Q is shunted with 10Ω
Q‘=10Q10+Q‘I=50cm ∴P=10Q10+Q×5050=10Q10+Q
23Q=10Q10+Q⇒Q=5Ω
∴P=103Ω