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Standard XII

Physics

Series Combination of Cells

In a mixed gr...

Question

In a mixed grouping of identical cells 5 rows are connected in parallel and each row contains 10 cells. This combination send a current i through an external resistance of $20 Ω$ . If the emf and internal resistance of each cell is 1.5 volt and $1 Ω$ respectively then the value of i is

0.14 A

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0.25 A

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0.75 A

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0.68 A

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Solution

The correct option is D 0.68 A
No. of cells in a row n = 10; No. of such rows m = 5
$i = \frac{n E}{(R + \frac{n r}{m})} = \frac{10 \times 1.5}{(20 + \frac{10 \times 1}{5})} = \frac{15}{22} = 0.68$ amp

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In a mixed grouping of identical cells 5 rows are connected in parallel and each row contains 10 cells. This combination send a current i through an external resistance of 20Ω. If the emf and internal resistance of each cell is 1.5 volt and 1Ω respectively then the value of i is

The correct option is D 0.68 ANo. of cells in a row n = 10; No. of such rows m = 5 i=nE(R+nrm)=10×1.5(20+10×15)=1522=0.68 amp

In a mixed grouping of identical cells 5 rows are connected in parallel and each row contains 10 cells. This combination send a current i through an external resistance of $20 Ω$ . If the emf and internal resistance of each cell is 1.5 volt and $1 Ω$ respectively then the value of i is

The correct option is D 0.68 A
No. of cells in a row n = 10; No. of such rows m = 5
$i = \frac{n E}{(R + \frac{n r}{m})} = \frac{10 \times 1.5}{(20 + \frac{10 \times 1}{5})} = \frac{15}{22} = 0.68$ amp