In a quadratic equation a x2-b x-c- if D-0- then find the roots-

The correct option is A b/2a, b/2a The roots of a quadratic equation are given as x = b ±√( D)/2a if D = 0, the equation reduces to, x = b ±√( 0 )/2a x ...

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Mathematics

Solving QE Using Quadratic Formula When D>0

In a quadrati...

Question

In a quadratic equation ax² + bx +c , if D = 0, then find the roots,

$\frac{- b}{2 a}, \frac{- b}{2 a}$

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$\frac{b}{2 a}, \frac{- b}{2 a}$

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$\frac{c}{2 a}, \frac{- c}{2 a}$

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$\frac{c}{2 a}, \frac{c}{2 a}$

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Solution

The correct option is A
$\frac{- b}{2 a}, \frac{- b}{2 a}$

The roots of a quadratic equation are given as $x = \frac{- b \pm \sqrt{D}}{2 a}$

if D = 0, the equation reduces to,
$x = \frac{- b \pm \sqrt{0}}{2 a} x = \frac{- b}{2 a}, \frac{- b}{2 a}$
Thus, the roots are real and equal.

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In a quadratic equation ax2 + bx +c , if D = 0, then find the roots,

The correct option is A −b2a,−b2a The roots of a quadratic equation are given as x=−b±√D2a if D = 0, the equation reduces to, x=−b±√02ax=−b2a,−b2a Thus, the roots are real and equal.

In a quadratic equation ax² + bx +c , if D = 0, then find the roots,

The correct option is A
$\frac{- b}{2 a}, \frac{- b}{2 a}$

The roots of a quadratic equation are given as $x = \frac{- b \pm \sqrt{D}}{2 a}$

if D = 0, the equation reduces to,
$x = \frac{- b \pm \sqrt{0}}{2 a} x = \frac{- b}{2 a}, \frac{- b}{2 a}$
Thus, the roots are real and equal.