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Byju's Answer
Standard XII
Chemistry
Percentage Composition
In a reaction...
Question
In a reaction, if
7
g of
C
O
is completely oxidised to
C
O
2
, the weight of
C
O
2
formed in
g
m
is:
A
14
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B
11
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C
44
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D
30
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Solution
The correct option is
B
11
C
O
+
1
2
O
2
→
C
O
2
The molecular weights of
C
O
and
C
O
2
are
28
g/mol and
44
g/mol respectively.
7 g of
C
O
corresponds to
0.25
moles. They react with oxygen to produce
0.25
moles of
C
O
2
.
0.25
moles of
C
O
2
corresponds to
11
g.
Suggest Corrections
0
Similar questions
Q.
One mole of a mixture of
C
O
and
C
O
2
requires exactly
20
g of
N
a
O
H
in solution for complete conversion of all the
C
O
2
into
N
a
2
C
O
3
. If the mixture (one mole) is completely oxidised to
C
O
2
, then weight of
N
a
O
H
to be used is:
Q.
7 g of CO on complete oxidation produces the following weight of
C
O
2
:
Q.
CO
2
(
g
)
+
H
2
(
g
)
→
CO
(
g
)
+
H
2
O
(
g
)
In the above reaction,
is the oxidising agent.
Q.
If the weight ratio of
C
and
O
2
present is 1:2 and both of reactants completely consume and form
C
O
and
C
O
2
and we will obtain a gaseous mixture of
C
O
and
C
O
2
. What would be the weight ratio of
C
O
and
C
O
2
in mixture?
Q.
0.8 mole of a mixture of
C
O
and
C
O
2
requires exactly 40 gram of
N
a
O
H
in solution for complete conversion of all the
C
O
2
into
N
a
2
C
O
3
. How many moles more of
N
a
O
H
would it require for conversion into
N
a
2
C
O
3
, if the mixture (0.8 mole) is completely oxidised to
C
O
2
:
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