In a reaction of $C_{6} H_{5} Y$ , the major product (>60%) is m-isomer, so the group Y is:

- C O O H

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- C l

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- O H

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- N H_{2}

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Solution

The correct option is A $- C O O H$
-COOH group has it's negative resonance effect as it tries to pull the electrons out of the ring. So meta product will be formed as ortho and para product will be unstable.

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C_{6} H_{5} Y,

- C O O H, - C N, - N H_{2} - C O C H_{3}, - N H C O C H_{3}, - O H, - C H O, - S O_{3} H, - C l, - N O_{2}

C H_{3} - N H_{2} + C O C l_{2} \to P r o d u c t

C H_{3} - C O O H

C H_{3} - C H_{2} - C H_{2} - O H

C H_{3} C H_{2} - C H_{2} . N H_{2}

C H_{3} - C H O

C H_{3} - C H_{2} - C H_{2} - O H

C H_{3} - C H_{2} - C H_{2} - O H

- O H

- C O O H

- C l

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