Question

In a rhombus $PQRS$, if $PQ=3x-7$ and $QR=x+3$, find $PS$

Answer 1

We know that in a rhombus, all sides are equal.

So, in rhombus $PQRS,$

$PQ=QR=RS=SP$

$\therefore$ $PQ=QR$

$\Rightarrow 3x-7=x+3$

$\Rightarrow 3x-x=3+7$

$\Rightarrow 2x=10$

$\Rightarrow x=5$

$PS=x+3$

$=5+3=8cm$