Question

In a rhombus $PQRS$, side $PQ=17cm$ and diagonal $PR=16cm$. Calculate the area of the rhombus.

• A. $240{cm}^2$
• B. $340{cm}^2$
• C. $280{cm}^2$
• D. $260{cm}^2$

Answer 1

The correct option is A $240{cm}^2$

Given: PQRS is rhombus. $PQ=17cmandPR=16cm$
Area of rhombus = $\frac{1}{2}p\sqrt{4a^2-p^2}$where p is the diagonal and a is side
Area of rhombus = $\frac{1}{2}\left(16\right)\sqrt{\left(4\right(17{)}^2-{16}^2)}$
Area of rhombus = $8\sqrt{900}$
Area of rhombus = $8\times 30$
Area of rhombus = $240$ $c{m}^2$