wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a series circuit C=2μF, L=1 mH and R=10 Ω, when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

A
1 : 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 : 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 : 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1 : 5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1 : 5
Current will be maximum in the condition of resonance so imax=VR=V10A
Energy stored in the coil WL=12Li2max=12L(V10)2
12×103(V2100)=12×105V2 joule
Energy stored in the capacitor
WC=12CV2=12×2×106 V2=106 V2 jouleWCWL=15

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Series RLC
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon