CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In a step-up transformer the turns ratio is 10. The input current of the transformer is 12.5 A and the frequency is 50 Hz. If the efficiency of the transformer is 80%, then the frequency of the output current will be

A
500 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
40 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
50 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 50 Hz
Given:

Turns ratio=10
Input current, IP=12.5 A
Frequency, fP=50 Hz
Efficiency of the transformer, η=80%

As, we know that in any transformer, the frequency of output current as well as the frequency of output voltage remains the same.
Only the magnitudes of voltage and current changes.

Hence, the frequency of current in the secondary coil will be 50 Hz.

Hence, option (D) is correct.

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image