Question

In a thermodynamic processes during each cycle , a heat engine absorbs 400 J of heat from a higher- temperature source and release 300 J of heat to the low-temperature sink. Calculate the efficiency of heat engine?

• A. $\frac{1}{7}$
• B. $\frac{1}{4}$
• C. $\frac{3}{7}$
• D. $\frac{4}{7}$
• E. $\frac{3}{4}$

Answer 1

Answer: (B)

$\frac{1}{4}$

The efficiency of heat engine, $\eta =\frac{W}{Q_1}=\frac{Q_1-Q_2}{Q_1}=\frac{400-300}{400}=1/4$