Question

In above shown circuit, there are three resistor 3$\Omega$, 6$\Omega$ and 4$\Omega$. Resistor are connected as shown in figure. Find the current through the 4$\Omega$ resistor.

• A. 2 A
• B. 4 A
• C. 6 A
• D. 8 A
• E. 12 A

Answer 1

Answer: (B)

4 A

Given : $R_1=3\Omega$ $R_2=6\Omega$ $R_3=4\Omega$ $V=24$ volts

Equivalent resistance between A and B $R_{AB}=\frac{R_1\times R_2}{R_1+R_2}=\frac{3\times 6}{3+6}=2\Omega$

Equivalent resistance of the whole circuit $R_{eq}=R_{AB}+R_3=2+4=6\Omega$

Current through $4\Omega$ resistor $I=\frac{V}{R_{eq}}=\frac{24}{6}=4$ A