Question

In above shown circuit, there are three resistor 3$\Omega$, 6$\Omega$ and 4$\Omega$. Resistor are connected as shown in figure. Find the voltage across the 4$\Omega$ resistor.

• A. 4 V
• B. 8 V
• C. 12 V
• D. 16 V
• E. 24 V

Answer 1

Answer: (D)

16 V

Given : $R_1=3\Omega$ $R_2=6\Omega$ $R_3=4\Omega$
Equivalent resistance of $3\Omega$ and $6\Omega$, $r_{eq}=\frac{3\times 6}{3+6}=2\Omega$

Thus voltage drop across $4\Omega$, $V^{\prime }=\frac{R_3}{R_3+r_{eq}}V=\frac{4}{2+4}\times 24=16$ volts