Question

In an $A.P.{17}^{th}$ term is $7$ more than its ${10}^{th}$ term. Find the common difference .

Answer 1

A] ${17}^{th}$ term = a+(17-1)d

${10}^{th}$ term = a+(10-1)d

$\therefore$ a+(17-1)d=a+(10-1)d+7

$\Rightarrow 16d=9d+7$

$\Rightarrow 7d=7$

$\therefore d=1$