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Question

In an AC circuit V and I is given by
V=1000sin(1000 t)volt
I=100sin(1000t+π6)mA
The power dissipation in the circuit in one complete cycle is.

A
25 W
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B
253
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C
100 W
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D
10 W
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Solution

The correct option is C 253
Power dissipation in an AC circuit in one complete cycle is given by ,
Pav=(1/2)V0I0cosϕ
given , V0=1000V,I0=100mA=0.1A,ϕ=π/6=300
Hence , Pav=(1/2)1000×0.1×cos30=50×(3/2)
or Pav=253

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