Question

In an elevator moving vertically up with an acceleration ${}^{\prime }{g}^{\prime }$, the force exerted on the floor by a passenger of mass $M$ is:-

• A. $Mg$
• B. $\frac{1}{2}Mg$
• C. zero
• D. $2Mg$

Answer 1

The correct option is D $2Mg$

Acceleration $=g$

Force exerted on the floor by $Y_a$

Mass$=M$

Upward$=Mg$

Downward$=Mg$

Total $=2Mg$