In an `n' sided polygon, the number of diagonals that can be drawn is equal to the number of sides. Then `n' is -
3
6
7
5
n(n−3)2= n ⇒ n = 5
The number of diagonals that can be drawn in an `n' sided polygon is 6 less than the number of diagonals that can be drawn in an (n + 1) sided polygon. The value of `n' is -
The number of diagonals that can be drawn in a (n-3) sided polygon is 1/3 times the number of diagonals that can be drawn in an `n' sided polygon. The value of `n' is -
If the number of diagonals that can be drawn in a polygon is 9, then what is the number of sides that the polygon has?