In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. The percentage of bromine in the compound is:

43%

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34.04%

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34%

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None of these

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Solution

The correct option is B
34.04%

Molar mass of AgBr = 108 + 80 = 188 g mol-1

188 g AgBr contains 80 g bromine

0.12 g AgBr contains= 80 X 0.12/188 g bromine

Percentage of bromine=80 X0.12 X100/188 X 0.15

= 34.04%

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In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. The percentage of bromine in the compound is:

The correct option is B 34.04% Molar mass of AgBr = 108 + 80 = 188 g mol-1 188 g AgBr contains 80 g bromine 0.12 g AgBr contains= 80 X 0.12/188 g bromine Percentage of bromine=80 X0.12 X100/188 X 0.15 = 34.04%

The correct option is B
34.04%

Molar mass of AgBr = 108 + 80 = 188 g mol-1

188 g AgBr contains 80 g bromine

0.12 g AgBr contains= 80 X 0.12/188 g bromine

Percentage of bromine=80 X0.12 X100/188 X 0.15

= 34.04%