Question

In chord $AB\cong chordCD$, prove that, $arcAC\cong arcBD$

Answer 1

Given : chord AB $\simeq$ chord CD.

$\Rightarrow$ length (arc AB minor) $=$ length (arc CD minor)

$\Rightarrow$ (arc AC) $+$ (arc CB) $=$ (arc CB) $+$ (arc BD)

$\Rightarrow$ length of arc (AC) $=$ length of arc (BD)

$\Rightarrow$ (arc AC) $\cong$ (arc BD)