Question

In common transistor circuit, the current gain is 0.98. On changing emitter current by 5.0 mA, the change in collector current is

• A. 3.5 mA
• B. 4.9 mA
• C. 6.3 mA
• D. 9.4 mA

Answer 1

The correct option is B 4.9 mA

Using $\alpha =\frac{\Delta I_C}{\Delta I_E}$
where $\alpha =0.98$

$\Delta I_C=5$ mA
$\Delta I_C=0.98\times 5\times {10}^{-3}$
$\Rightarrow =4.9$ mA