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Standard XII

Physics

Electric Potential Due to Shell

In copper, ea...

Question

In copper, each atom releases one electron. If a current of 1.1A is flowing in the copper wire of diameter 1mm then the drift velocity of electrons, will approximately be (density of copper $= 9 \times 10^{3} K g m^{- 3}$ and its atomic weight $= 63)$ .

10.3 mm/s

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0.1 mm/s

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0.2 mm/s

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0.2 cm/s

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Solution

The correct option is A 0.1 mm/s
Electron density $n = \frac{N_{A} ρ}{M} = \frac{(6.023 \times 10^{23}) \times (9 \times 10^{3})}{63 \times 10^{- 3}} = 0.86 \times 10^{29} m^{- 3}$

Drift velocity $v_{d} = \frac{I}{n e A} = \frac{1.1}{(0.86 \times 10^{29}) \times (1.6 \times 10^{- 19}) \times π (0.5 \times 10^{- 3})^{2}} = 0.1 \times 10^{- 3} m / s = 0.1$ mm/s

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Similar questions

Q. Every atom makes one free electron in copper. If

1.1

ampere current is flowing in the wire of copper having 1mm diameter, then the drift velocity (approx) will be (density of copper =

9 \times 10^{3} k g / m^{3}

and atomic weight of copper =

63

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Copper has one conduction electron per atom. Its density is $8.89 g / m^{3}$ and its atomic mass is 63.54 g/mol. lf a copper wire of diameter 1.0 mm carries a current of 2.0 A. What is the drift speed of the electrons in the wire?

Q. Current is flowing with a current density

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in a copper wire. Assuming that each copper atom contribution one free electron and gives that Avogadro number

= 6.0 \times 10^{23} a t o m s / m o l e

Density of copper

= 9.0 g / c m^{3}

.Atomic weight of copper

= 64 g / m o l e

Electronic charge

= 1.6 \times 10^{- 19}

coulomb. The drift velocity of electrons is:

Q. A current of

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exists in a copper wire of cross-section

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(

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A current of 1.0 A exists in a copper wire of cross - section 1.0 $m m^{2}$ . Assuming one free electron per atom calculate the drift speed of the free electrons in the wire. The density of copper is 9000 $k g m^{- 3}$ .

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In copper, each atom releases one electron. If a current of 1.1A is flowing in the copper wire of diameter 1mm then the drift velocity of electrons, will approximately be (density of copper =9×103Kgm−3 and its atomic weight =63).

The correct option is A 0.1 mm/sElectron density n=NAρM=(6.023×1023)×(9×103)63×10−3=0.86×1029m−3Drift velocity vd=IneA=1.1(0.86×1029)×(1.6×10−19)×π(0.5×10−3)2=0.1×10−3m/s=0.1 mm/s

In copper, each atom releases one electron. If a current of 1.1A is flowing in the copper wire of diameter 1mm then the drift velocity of electrons, will approximately be (density of copper $= 9 \times 10^{3} K g m^{- 3}$ and its atomic weight $= 63)$ .