In - ABC if- sin B-sin C-2cos A then the triangle is

The correct option is B isosceles sin nbsp; B=2 cos nbsp; A sin nbsp; C sin nbsp; B=sin (A+C) sin(A C) sin nbsp; B=sin (π B) sin(A C) ...

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Sum of Trigonometric Ratios in Terms of Their Product

In Δ ABC if...

Question

In $Δ A B C$ if, $\frac{sin B}{sin C} = 2 cos A$ then the triangle is

right angled

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isosceles

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equilateral

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scalene

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Solution

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Similar questions

Δ A B C

cos A = \frac{sin B}{sin C}

Δ A B C,

\frac{cos A + 2 cos C}{cos A + 2 cos B} = \frac{sin B}{sin C}

Δ A B C, 2 cos A sin C = sin B

Δ A B C

sin A + sin B + sin C = \sqrt{2} + 1

cos A + cos B + cos C = \sqrt{2}

Δ A B C

\sum \frac{\sqrt{sin} A}{\sqrt{sin B} + \sqrt{sin C} - \sqrt{sin A}} \geq 3

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