wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In fission of one uranium-235 nucleus, the loss in mass is 0.2amu. Calculate the energy released.


A

186.2 MeV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

182.6 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

156.4 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

189.1 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

186.2 MeV


Step 1: Given data

Loss in mass in the fission of one uranium-235 nucleus, m=0.2amu

Step 2: Finding the energy released

In a nuclear fission reaction, the mass defect is converted into energy.

Given the mass unit and the energy, the equivalent is 1amu=931MeV

Thus the energy released for 0.2amu is E=0.2amu×931MeV

=186.2MeV

So the energy released is 186.2 MeV. Thus A is the correct option.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nuclear Fission
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon