In one of the following compounds, the oxidation number of sulphur is not a whole number. The compound is:

N a_{2} S_{4} O_{6}

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H_{2} S O_{5}

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H_{2} S O_{4}

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N a_{2} S_{2} O_{3}

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Solution

The correct option is C $N a_{2} S_{4} O_{6}$
Compound Oxidation number of $S$
$N a_{2} S_{4} O_{6}$ $+ 2.5$
$H_{2} S O_{5}$ $6$
$H_{2} S O_{4}$ $6$
$N a_{2} S_{2} O_{3}$ $2$
Therefore, we can see that the oxidation number of $N a_{2} S_{4} O_{6}$ is not a whole number.

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Calculate the oxidation number of sulphur, chromium and nitrogen in H₂SO₅,–. Suggest structure of these compounds. Count for the fallacy.

S

N a_{2} S_{2} O_{3}

N a_{2} S_{4} O_{6}

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