Question

In Reimer-Tiemann reaction, reactants are:

• A. phenol, $CHC{l}_3$ and alkali
• B. phenol, $CC{l}_4$ and alkali
• C. aniline, $CHC{l}_3$ and alkali
• D. both Phenol, $CHC{l}_3$ and alkali and phenol, $CC{l}_4$ and alkali

Answer 1

The correct option is D both Phenol, $CHC{l}_3$ and alkali and phenol, $CC{l}_4$ and alkali

In Reimer-Tiemann reaction, reactants are both Phenol, $CHC{l}_3$ and alkali and phenol, $CC{l}_4$ and alkali.

When phenol, $CHC{l}_3$ and alkali are used, the product is salicylaldehyde.

When phenol, $CC{l}_4$ and alkali are used, the product is salicylic acid.

Option D is correct.