Question

The dipole moments of $CC{l}_4,CHC{l}_3$ and $C{H}_4$ are in the order:

• A. $C{H}_4<CC{l}_4<CHC{l}_3$
• B. $C{H}_4=CC{l}_4<CHC{l}_3$
• C. $CC{l}_4<C{H}_4<CHC{l}_3$
• D. $CHC{l}_3<C{H}_4=CC{l}_4$

Answer 1

The correct option is B $C{H}_4=CC{l}_4<CHC{l}_3$

All the three compounds possess a tetrahedral geometry. In both $CC{l}_4$ and $C{H}_4$, ${\mu }_{net}=0$, whereas in $CHC{l}_3,{\mu }_{net}>0$.