In square $P Q R S$
if $P Q = 3 x - 7$ and $Q R = x + 3$ ; find $P S$

Open in App

Solution

In the square, all sides are of equal length

$\Rightarrow P Q = Q R \Rightarrow 3 x - 7 = x + 3 \Rightarrow 2 x = 10 \to x = 5$

$\to P S = P Q = 3 (5) - 7 = 15 - 7 = 8$

Suggest Corrections

Similar questions

= 3 x - 7

Q R = x + 3

P Q R S

P Q = 3 x - 7

Q R = x + 3

P S

P Q R S

P Q = 3 y - 7

Q R = y + 3

P S

P R = 5 x

Q S = 9 x - 8

Q S

$If P Q = 3 x - 7 and Q R = x + 3; find PS$

$In square PQRS : (i) i f P Q = 3 x - 7 a n d Q R = x + 3; f i n d P S (i i) i f P R = 5 x a n d Q R = 9 x - 8. F i n d Q S$

Join BYJU'S Learning Program