CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Newton's Laws of Motion

In the adjoin...

Question

In the adjoining figure $m_{1} = 4 m_{2}$ . The pulleys are smooth and light. At time t = 0, the system is at rest. If the system is released and if the acceleration of mass m₁ is a, then the acceleration of $m_{2}$ will

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
Since the mass $m_{2}$ travels double distance in comparison to mass $m_{1}$ therefore its acceleration will be double i.e. 2a

Suggest Corrections

thumbs-up

9

Similar questions

Q. In the figure

m_{1} = 4 m_{2}

. The pulleys are smooth and light. At time

t = 0

, the system is at rest. If the system is released, the acceleration of mass

m_{1}

Q. In the figure mass

m_{1} = 4

m_{2}

. The pulleys are smooth and light and thread is also light. At time

t = 0

, the system is at rest in the positions of the masses as in the figure. If the system is released, find the maximum height reached by the mass

m_{2}

(g = 10 m s^{- 2})

.

m_{1}

m_{2}

(m_{1} > m_{2})

are connected to the ends of a light inextensible string which passes over the surface of a smooth fixed pulley. If the system is released from rest, the acceleration of the center of mass of the system will be (

g =

acceleration due to gravity)

Q. A light string passing over a smooth light pulley connects two blocks of masses

m_{1}

m_{2}

m_{1}

m_{2}

). The masses are moving vertically. If the acceleration of the system is g/8, then ___________

Q. A light string passing over the smooth pulley connects two blocks of masses

m_{1}

m_{2}

(m_{2} > m_{1})

(vertically). If the acceleration of the system is

g / 8

. Then the ratio of masses (

\frac{m_{2}}{m_{1}})

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

PHYSICS

Watch in App

explore_more_icon

Explore more

Newton's Laws of Motion

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon