In the circuit shown- the diodes are ideal- A1 and A2 are ammeters of resistance 5- each- The potentials of the points A- B- C and D are VA- VB- VC and VD respectively- -VA-VB-10V

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In the circui...

Question

In the circuit shown, the diodes are ideal. $A_{1}$ and $A_{2}$ are ammeters of resistance $5 Ω$ each. The potentials of the points A, B, C and D are $V_{A}, V_{B}, V_{C}$ and $V_{D}$ respectively. $| V_{A} - V_{B} | = 10 V$

A_{1}

and

A_{2}

will always show the same reading

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the readings of

A_{1}

and

A_{2}

will depend on whether

V_{A} > V_{B}

V_{A} < V_{B}

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the readings of either of

A_{1}

A_{2}

or both will be

1 A

in all cases

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V_{A} > V_{B}, A_{1}

will show no deflection

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Solution

The correct options are
B the readings of either of $A_{1}$ or $A_{2}$ or both will be $1 A$ in all cases
C the readings of $A_{1}$ and $A_{2}$ will depend on whether $V_{A} > V_{B}$ or $V_{A} < V_{B}$
D If $V_{A} > V_{B}, A_{1}$ will show no deflection
If we remove the two branches containing the ammeters, then, for $V_{A} > V_{B}$ ,
$V_{A} - V_{C} = 3 \times \frac{10}{7}$ and $V_{A} - V_{D} = 1 \times \frac{10}{3}$ .
$∴ V_{D} - V_{C^{'}} = 10 (\frac{3}{7} - \frac{1}{3}) > 0$
or $V_{D} > V_{C^{'}}$ and current flows only through $A_{2}$ .
Similarly, if $V_{B} > V_{A}, V_{C} > V_{D}$ , and current flows only through $A_{1}$ .
For current flowing through either $A_{1}$ or $A_{2}$ , the total resistance is $10 Ω$ and current is $1 A$ .

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In the circuit shown, the diodes are ideal. A1 and A2 are ammeters of resistance 5Ω each. The potentials of the points A, B, C and D are VA,VB,VC and VD respectively. |VA−VB|=10V

In the circuit shown, the diodes are ideal. $A_{1}$ and $A_{2}$ are ammeters of resistance $5 Ω$ each. The potentials of the points A, B, C and D are $V_{A}, V_{B}, V_{C}$ and $V_{D}$ respectively. $| V_{A} - V_{B} | = 10 V$