In the circuit, the potential difference across $P Q$ will be nearest to :

9.6 V

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6.6 V

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4.8 V

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3.2 V

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Solution

The correct option is A $3.2 V$
Potential difference across PQ i.e., potential difference across the resistance of $20 Ω$ which is $V = i \times 20$
$i = \frac{48}{100 + 100 + 80 + 20}$
$= 0.16 A$
$V = 0.16 \times 20 = 3.2 V$

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In the circuit, the potential difference across PQ will be nearest to :

The correct option is A 3.2VPotential difference across PQ i.e., potential difference across the resistance of 20Ω which is V=i×20i=48100+100+80+20=0.16AV=0.16×20=3.2V

In the circuit, the potential difference across $P Q$ will be nearest to :

The correct option is A $3.2 V$
Potential difference across PQ i.e., potential difference across the resistance of $20 Ω$ which is $V = i \times 20$
$i = \frac{48}{100 + 100 + 80 + 20}$
$= 0.16 A$
$V = 0.16 \times 20 = 3.2 V$