Question

In the compound,$\stackrel{6}{C}{H}_2=\stackrel{5}{C}H-\stackrel{4}{C}{H}_2-\stackrel{3}{C}{H}_2-\stackrel{2}{C}\equiv \stackrel{1}{C}H$, $C_2-C_3$ bond is of :

• A. $sp-s{p}^2$
• B. $sp-s{p}^3$
• C. $s{p}^2-s{p}^3$
• D. $s{p}^3-s{p}^3$

Answer 1

The correct option is B $sp-s{p}^3$

The chain is
$\stackrel{6}{C}{H}_2=\stackrel{5}{C}H-\stackrel{4}{C}{H}_2-\stackrel{3}{C}{H}_2-\stackrel{2}{C}\equiv \stackrel{1}{C}H$

Hence, $C_2-C_3$ are $sp-s{p}^3$ hybridised.