Question

In the coordination compound $K_4\left[Ni\right(CN{)}_4]$, the oxidation state of $Ni$ is :

• A. $-1$
• B. 0
• C. $+1$
• D. $+2$

Answer 1

Answer: (B)

0

Let the oxidation number of $Ni$ in $K_4\left[Ni\right(CN{)}_4]$ = $x$

$(+1)\times 4+x+(-1)\times 4=0$

$4+x-4$ = 0

$x=0$

Therefore, in the coordination compound, the oxidation state of $Ni$ is $0$

So, the correct option is $B$