wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the electric circuit shown in the figure, power dissipated in 4 Ω resistor is :

79970_790c15de3b844e31b8bdd95feb1a9927.png

A
4 W.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4 W.
The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.
Rp=(8×8)(8+8)=4ohms
This resistor is connected in series with the 4 ohm resistor R1. The total resistance Rt of the circuit is then
Rt =R1+Rp=4+4 = 8 ohms.
Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be equal to the current of the battery. Using Ohms law we get,
I=VR=88=1A.
Hence, the current flowing through the resistor R1 (4 ohms) is 1A.
Now the power dissipated in the resistor R1 (4 ohms) is given as follows.
P=I2R=12×4=1×4=4W.
Hence, the power dissipated in the resistor R1 (4 ohms) = 4W.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Heating Effect of Electric Current
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon