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Question

In the figure the position time graph of a particle of mass 0.1 kg is shown. Find the impulse at t=4 sec :

133716_7729ac4bb3144eff81e9039149067d26.png

A
0.2 kgcms1
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B
0.2 kgcms1
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C
0.1 kgcms1
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D
0.4 kgcms1
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Solution

The correct option is B 0.2 kgcms1
Just before 4 seconds, velocity of particle =2 cm/s (slope of graph).
Just after 4 seconds, velocity =0.
Thus change in velocity at 4 seconds =2 cm/s
Thus impulse =mΔv
or, Impulse=0.1×2=0.2 kgcm/s

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