wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure the position time graph of a particle of mass 0.1 kg is shown. Find the impulse at t=4 sec :

133716_7729ac4bb3144eff81e9039149067d26.png

A
0.2 kgcms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.2 kgcms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.1 kgcms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.4 kgcms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.2 kgcms1
Just before 4 seconds, velocity of particle =2 cm/s (slope of graph).
Just after 4 seconds, velocity =0.
Thus change in velocity at 4 seconds =2 cm/s
Thus impulse =mΔv
or, Impulse=0.1×2=0.2 kgcm/s

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Momentum Returns
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon