In the figure the position time graph of a particle of mass 0.1kg is shown. Find the impulse at t=4sec :
A
0.2kgcms−1
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B
−0.2kgcms−1
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C
0.1kgcms−1
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D
−0.4kgcms−1
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Solution
The correct option is B−0.2kgcms−1 Just before 4 seconds, velocity of particle =2cm/s (slope of graph). Just after 4 seconds, velocity =0. Thus change in velocity at 4 seconds =−2cm/s Thus impulse =mΔv or, Impulse=0.1×−2=−0.2kgcm/s