You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Galvanometer

In the figure...

Question

In the figure, the potentiometer wire AB of length L & resistance 9r is joined to the cell D of emf E & internal resistance r. The emf of the cell C is E / 2 & its internal resistance is 2r. The galvanometer G will show no deflection when the length AM is

4L/9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5L/9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7L/18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11L/18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
5L/9

$I_{w} = \frac{E}{10 r}; V_{w} = I_{w} 9 r = \frac{9 E}{10 L}$

$∴$ potential gradient $= \frac{9 E}{10 L}$

For balance, $\frac{E}{2} = (A M) \frac{9 E}{10 L} \Rightarrow A M = \frac{5}{9} L$

Suggest Corrections

Similar questions

Q. In the figure, the potentiometer wire

A B

of length

L

and resistnace

9 r

is joined to the cell

D

of e.m.f and internal resistance

r

. The cell

C

's emf is

ε / 2

and its internal resistance is

2 r

.
The galvanometer

G

will show no deflection when the length

A J

Q. In the figure, the potentiometer wire

A B

of length

L

and resistance

9 r

is joined to the cell

D

of emf

ε

and internal resistance

r

. The cell

C^{'} s

emf is

ε / 2

and its internal resistance is

2 r

. The galvanomater

G

will show no deflection when the length

A J

Q. In the fig. the potentiometer wire

A B

of length

L

& resistance

9 r

is joined to the cell

D

of e.m.f.

ε

and internal resistance

r

. The cell

C s

e.m.f. is

ε / 2

and its internal resistance is

2 r

. The galvanometer

G

will show no deflection then find length

A J

Q. A potentiometer wire

A B

having length

L

and resistance

12 r

is joined to a cell

D

of emf

ϵ

and internal resistance

r

. A cell

C

having emf

ϵ / 2

and internal resistance

3 r

is connected. The length

A J

at which the galvanometer as shown in fig. shows no deflection is

Q. In the figure, the potentiometer wire of length 1000 cm and resistance 9 ohm is joined to a cell of emf 2V and internal resistance of 1 ohm. The galvanometer G will show null deflection when the length AC is

Join BYJU'S Learning Program

In the figure, the potentiometer wire AB of length L & resistance 9r is joined to the cell D of emf E & internal resistance r. The emf of the cell C is E / 2 & its internal resistance is 2r. The galvanometer G will show no deflection when the length AM is

The correct option is B 5L/9 Iw=E10r;Vw=Iw9r=9E10L ∴ potential gradient =9E10L For balance, E2=(AM)9E10L ⇒AM=59L

The correct option is B
5L/9

$I_{w} = \frac{E}{10 r}; V_{w} = I_{w} 9 r = \frac{9 E}{10 L}$

$∴$ potential gradient $= \frac{9 E}{10 L}$

For balance, $\frac{E}{2} = (A M) \frac{9 E}{10 L} \Rightarrow A M = \frac{5}{9} L$