Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
$I.4x^4-5x^2+1=0$
$II.2y^2+11y+14=0$

• A. x > y
• B. x y
• C. x < y
• D. x y
• E. x = y or the relationship between 'x' & 'y' cannot be determined

Answer 1

The correct option is A x > y

$4x^4-5x^2+1=0(x^2-1)(4x^2-1)=0x=1,-1,\frac{1}{2},-\frac{1}{2}\Rightarrow 2y^2+11y+14=0y=-2,-\frac{7}{2}$
Least value of x = $-1>-2$= Largest value of y
So,$x>y.$