In the following reaction $[C u (H_{2} O)_{4}]^{2 +} (a q) + H C O_{3}^{-} (a q) ⇌ [C u (H_{2} O)_{4} O H^{-}]^{+} (a q) + H_{2} C O_{3} (a q)$
species behaving as a bronsted- lowry acid are:

[C u (H_{2} O)_{4}]^{2 +}, H C O_{3}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C O_{3}^{-}, [C u (H_{2} O)_{4} O H^{-}]^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C u (H_{2} O)_{4}]^{2 +}, H_{2} C O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[H C O_{3}^{-}, H_{2} C O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $[C u (H_{2} O)_{4}]^{2 +}, H_{2} C O_{3}$
According to Bronsted- lowry acid concept acids are ions or molecules which have tendency to donate protons.
$[C u (H_{2} O)_{4}]^{2 +}$ will donate a proton to $H C O_{3}^{-}$
so, $H C O_{3}^{-}$ (base) changes to $H_{2} C O_{3}$ (acid)
hence both $[C u (H_{2} O)_{4}]^{2 +}$ and $H_{2} C O_{3}$ behaving as a bronsted- lowry acid.

Suggest Corrections

Similar questions

[C u (H_{2} O)_{4}]^{2 +} (a q) + H C O_{3}^{-} (a q) ⇌ [C u (H_{2} O)_{4} O H^{-}]^{+} (a q) + H_{2} C O_{3} (a q)

{NH}_{3} (aq) + H_{2} O (l) \to {NH}_{4}_{4}^{+} (aq) + {OH}^{-} (aq)

H C O_{3}^{-} (a q .) + O H^{-} (a q .) \to C O_{3}^{2} (a q .) + H_{2} O

H N O_{3} (a q) + H_{2} O (l) \to H_{3} O^{+} (a q) + N O_{3}^{-} (a q)

N H_{3} (g) + H C l (g) \to N H_{4}^{+} (s) + C l^{-} (s)

{Cl}^{-} + H^{+} \to HCl (aq)

{CH}_{3} COOH (aq) \to {CH}_{3} {COO}^{-} + H^{+}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program