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Oxides of Nitrogen

In the follow...

Question

In the following reaction identify compounds $A, B, C$ and $D$ :
$P {C l}_{5} + S O_{2} ⟶ A + B$ ;
$A + C H_{3} C O O H ⟶ C + S O_{2} + H C l$
$2 C + {(C H_{3})}_{2} C d ⟶ D + C d {C l}_{2}$

S O {C l}_{2}, P O {C l}_{3}, C H_{3} C O C l, C H_{3} C O C H_{3}

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S O {C l}_{2}, H C l, C H_{3} C l, C H_{3} C H O

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S O_{2}, {C l}_{2}, C_{2} H_{5} C l, C H_{3} C O C H_{3}

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None of these

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Solution

The correct option is A $S O {C l}_{2}, P O {C l}_{3}, C H_{3} C O C l, C H_{3} C O C H_{3}$
The compounds $A, B, C$ and $D$ are $S O {C l}_{2}, P O {C l}_{3}, C H_{3} C O C l, C H_{3} C O C H_{3}$ respectively.
The reactions are as shown below:
Phosphorous pentachloride reacts with sulphur dioxide to form thionyl chloride and phosphorous oxychloride.
$P {C l}_{5} + S O_{2} ⟶ S O {C l}_{2} A + P O {C l}_{3} B$

Thionyl chloride reacts with acetic acid to form acetyl chloride, sulphur dioxide and hydrogen chloride gas.
$S O {C l}_{2} A + C H_{3} C O O H ⟶ C H_{3} C O C l C + S O_{2} + H C l$
Acetyl chloride reacts with dimethyl cadmium to form acetone and cadmium (II) chloride.
$2 C H_{3} C O C l C + {(C H_{3})}_{2} C d ⟶ 2 C H_{3} C O C H_{3} D + C d {C l}_{2}$

Suggest Corrections

Similar questions

A + S O C l_{2} \to B + S O_{2} + H C l

A + N a \to C + H_{2}

B + C \to (C_{2} H_{5})_{2} O + N a C l

A

(i) P {C l}_{5} + {S O}_{2} \to A + B

(i i) A + M e C O O H \to C + {S O}_{2} + H C l

(i i i) 2 C + {M e}_{2} C d \to 2 D + C D {C l}_{2}

{C H}_{3} C H = {C H}_{2} + I C l ⟶

{C l}_{2} + h o t N a O H ⟶

{C l}_{2} + S^{2 -} ⟶

{S O}_{2} + I_{2} + H_{2} O ⟶

{S n C l}_{2} + H C l + I_{2} ⟶

H_{2} S

H C l

N H_{3}

C l_{2}

C H_{3} C O O H

C H_{3} C H O

C a C O_{3} + H C l \to C a C l_{2} + H_{2} O + C O_{2}

M n O_{2} + H C l \to M n C l_{2} + H_{2} O + C l_{2}

M g (O H)_{2} + H C l \to M g C l_{2} + H_{2} O

K I + H_{2} S O_{4} \to K H S O_{4} + I_{2} + S O_{2}

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