In the following reaction, identify the species oxidised, the species reduced, the oxidising agent and the reducing agent.
$H_{2} S O_{3} + 2 H_{2} S \to 3 S + 3 H_{2} O$ .

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Solution

$H_{2} S O_{3} + 2 H_{2} S = 3 S + 3 H_{2} O$
Writing oxidation numbers on various atoms,
$H_{2} S O_{3}$ is reduced, i.e., it acts as oxidising agent. $H_{2} S$ is Oxidised, i.e., it acts as reducing agent.

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