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Kirchhoff's Junction Law

In the given ...

Question

In the given circuit if point C is connected to the earth and a potential of $+ 2000 V$ is given to the point A, the potential at B is :

1500 V

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1000 V

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500 V

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400 V

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Solution

The correct option is C $500 V$
As the capacitors 5 and 15 are in series so potential across 5 is $V_{A} - V_{B} = \frac{C_{2}}{C_{1} + C_{2}} (V_{A} - V_{C})$
or, $2000 - V_{B} = \frac{15}{5 + 15} (2000 - 0)$
or $2000 - V_{B} = 1500 \Rightarrow V_{B} = 2000 - 1500 = 500 V$

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