Question

In the given figure, $AOB$ is a straight line and the ray $OC$ stands on it. If $\angle BOC={132}^o$, then $\angle AOC=?$

• A. ${68}^o$
• B. ${48}^o$
• C. ${42}^o$
• D. None of these

Answer 1

The correct option is B ${48}^o$

Given, $\angle BOC={132}^o$

$\angle AOC$ = ?

We can write,

$\angle AOC+\angle BOC$ = ${180}^o$....$[\because Linearpair]$

$\Rightarrow \angle AOC+{132}^o$ = ${180}^o$

$\Rightarrow \angle AOC$ = ${180}^o-{132}^o$

$\Rightarrow \angle AOC$ = ${48}^o$

Hence, the required answer is ${48}^o$