In the given figure PA = 4 cm and PB = 9 cm, the value of PT is equal to
A
5 cm
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B
6 cm
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C
7 cm
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D
4 cm
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Solution
The correct option is B 6 cm If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then PA×PB=PT2
Substituting the value we get 4×9=PT2 PT2=36 PT=6cm