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Question

In the metre bridge arrangement, an unknown resistance R1 is connected in series with resistance of 10 Ω. When the combination is connecetd to left gap of the meter bridge and R2 is connected to right gap, balance point from left end is at 50 cm. When 10 Ω resistor is removed, the balance point shifts to 40 cm. The value of R1 is

A
20 Ω
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B
10 Ω
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C
60 Ω
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D
40 Ω
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Solution

The correct option is A 20 Ω
R1+10R2=5050

R1+10=R2 ...(1)

Now, when 10 Ω is removed, then

R1R2=4060

R1R2=23

R2=32R1 ...(2)

Put (2) in (1), we get

R1+10=32R1

2R1+20=3R1

R1=20 Ω

Hence, the correct answer is (A).

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