In the oxidation of $N_{2} H_{4}$ to $N_{2}$ , equivalent weight of $N_{2} H_{4}$ would be ________ .

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Solution

In the oxidation of $N_{2} H_{4}$ to $N_{2}$ , equivalent weight of $N_{2} H_{4}$ would be 8.
The oxidation state of N in hydrazine and nitrogen molecule is -2 and 0 respectively. Hence, the total change in the oxidation number per molecule of hydrazine is 4.

The equivalent mass of hydrazine $= \frac{Formula mass of hydrazine}{total change in the oxidation number of nitrogen per molecule of hydrazine} = \frac{32}{4} = 8$
Hence, the equivalent weight of hydrazine will be 8.

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