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Stoichiometric Calculations

In the reacti...

Question

In the reaction:
$C a C O_{3} + H_{2} S O_{4} \to C a S O_{4} + H_{2} O + C O_{2}$
Calculate the amount (in g) of $H_{2} S O_{4}$ required to decompose $10 g C a C O_{3}$

9.8

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10.8

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980

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Solution

The correct option is A 9.8
According to the reaction, 1 mol of $C a C O_{3}$ reacts with 1 mol of $H_{2} S O_{4}$
i.e., $100 g$ of $C a C O_{3}$ react with $98 g$ of $H_{2} S O_{4}$
So, $10 g$ of $C a C O_{3}$ will require $(\frac{98}{100} \times 10) = 9.8 g$ of $H_{2} S O_{4}$

Suggest Corrections

Similar questions

C a C O_{3} + H_{2} S O_{4} \to C a S O_{4} + H_{2} O + C O_{2}

H_{2} S O_{4}

10 g C a C O_{3}

C a C O_{3} + H_{2} S O_{4} \to C a S O_{4} + H_{2} O + C O_{2}

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10 g C a C O_{3}

H_{2} S O_{4}

98 %

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1

0.1 M

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N a O H

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6.13 M H_{2} S O_{4}

H_{2} S O_{4} = 98 g / m o l

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