Question

In the reaction NaOH (hot and conc.) $+C{l}_2\to NaCl+NaCl{O}_3$
Change in oxidation state of $C{l}_2$ is :

• A. $0$ to $-1$ and $+5$
• B. $0$ to $1$ and $+3$
• C. $0$ to $0$ and $-1$
• D. $0$ to $1$ and $+7$

Answer 1

The correct option is A $0$ to $-1$ and $+5$

$\begin{array}{ccccccc}O{H}^{-}& +& C{l}_2& \to & C{l}^{-}& +& Cl{O}_3^{-}\\ & & 0& & -1& & +5\end{array}$